(3x^2+17x+19)/(x+4)

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Solution for (3x^2+17x+19)/(x+4) equation:


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(3*x^2+17*x+19)/(x+4) = 0

3*x^2+17*x+19 = 0

3*x^2+17*x+19 = 0

DELTA = 17^2-(3*4*19)

DELTA = 61

DELTA > 0

x = (61^(1/2)-17)/(2*3) or x = (-61^(1/2)-17)/(2*3)

x = (61^(1/2)-17)/6 or x = (-(61^(1/2)+17))/6

(x+(61^(1/2)+17)/6)*(x-((61^(1/2)-17)/6)) = 0

((x+(61^(1/2)+17)/6)*(x-((61^(1/2)-17)/6)))/(x+4) = 0

( x+(61^(1/2)+17)/6 )

x+(61^(1/2)+17)/6 = 0 // - (61^(1/2)+17)/6

x = -((61^(1/2)+17)/6)

( x-((61^(1/2)-17)/6) )

x-((61^(1/2)-17)/6) = 0 // + (61^(1/2)-17)/6

x = (61^(1/2)-17)/6

x in { -((61^(1/2)+17)/6), (61^(1/2)-17)/6 }

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